How many terms of an AP must be taken for their sum to be equal to 120 if its 3rd term is 9 and difference between the 7th and 2nd term is 20?
8 terms of an AP must be taken for their sum to be equal to 120.How many terms of an AP must be taken for their sum to be equal to 200 if its third term is 16 and the difference between the 6th and the 1stterm is 30?
1 Answer. Explanation: If the difference between the 6th and the 1st term is 30, it means that the common difference is equal to 6. Since, the third term is 16, the AP would be 4, 10, 16, 22, 28, 34, 40, 46 and the sum to 8 terms for this AP would be 200.How many terms of AP must be added to get the sum?
Hence, 15 terms of the AP must be added to get the sum 0.How many terms of AP 18 16 14 take so their sum is zero?
Therefore 19 terms of the sequence has to be taken so that their sum is zero.Episode 12: How Many Terms of an Arithmetic Sequence are Required to Equal a Given Sum?
How many terms of AP 65 60 55 Take that their sum is zero?
As the number of terms cannot be zero therefore total number of terms will be 27.How many terms of the AP 18 16 14 12 are needed to give the sum 78 explain the double answer?
The sum of 78 can be attained by either adding 6 terms or 13 terms so that negative terms from T11 onward decrease the maximum sum to 78.How many terms of an AP 9 17/25 must be taken to give a sum of 636?
12 terms must be taken for AP. 9, 17, 25 ... to give a sum of 636.How many terms of the AP 63 60 5754 must be taken so that their sum is 693 explain the double answer?
Solution. The given AP is 63, 60, 57, 54,……….. So, the sum of 21 terms as well as that of 22 terms is 693.How many terms of the AP 1715 1311 must be added to get the sum 72 explain the double answer?
So we can see that the sum of 6 terms and sum of 12 terms is 72.How many terms of an AP must be taken so that their sum is 78?
Now we have to find out the number of terms in the A.P if the sum of an A.P is 78. Where symbols have their usual meanings. So the number of terms of the A.P so that their sum is 78 are 4 and 13. So this is the required answer.How many terms of the AP must be taken so that their sum is 120?
Hence, for n = 10 the sum is 120 for the given AP.How many terms of the AP 5 10 15 must be taken to give a sum of 525?
Ans. (Therefore, sum of first 15 terms of AP is equal to 525.